2019 Jacksonville mayoral election
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Turnout | 24% | ||||||||||||||||||||||||||||||||||
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Results by precinct Curry: 30–40% 40–50% 50–60% 60–70% 70–80% 80–90% Brosche: 30–40% 40–50% | |||||||||||||||||||||||||||||||||||
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Elections in Florida |
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Government |
The 2019 Jacksonville mayoral election was held on March 19, 2019, to elect the mayor of Jacksonville. Incumbent mayor Lenny Curry, a Republican, won a majority of votes to win a second term in office. No Democratic candidate qualified for the mayoral election.
Candidates
Republican Party
Declared
- Lenny Curry, incumbent mayor
- Anna Brosche, member of Jacksonville City Council
- Jimmy Hill, small business owner and president of International Association of Fire Fighters Local 2622
Democratic Party
While Democratic candidates did declare their candidacy, no Democratic candidates qualified for the mayoral election in 2019.
Declared
- Doreszell Cohen, founder of Citizens for Criminal Justice Reform
- Yolanda Thornton, small business owner
Declined
- Alvin Brown, former mayor of Jacksonville
- Garrett Dennis, member of Jacksonville City Council
Independents
Declared
- Omega Allen, Chair of the NW Jacksonville Economic Development Trust Fund
- Connell Crooms, nonprofit director
- Vishaun Grissett, independent consultant
Campaign and results
Democrats did not field a candidate for Mayor of Jacksonville in the 2019 election. Curry faced Anna Lopez Brosche, described by The Florida Times-Union as a moderate Republican. Brosche's campaign received support from some Democratic politicians, including city councilman Garrett Dennis and former Duval County Democratic Party chair Lisa King.
Party | Candidate | Votes | % | |
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Republican | Lenny Curry (incumbent) | 84,545 | 57.62 | |
Republican | Anna Lopez Brosche | 35,404 | 24.13 | |
Independent | Omega Allen | 15,453 | 10.53 | |
Republican | Jim Hill | 11,056 | 7.54 | |
write-in | Michael Romero | 263 | 0.18 | |
Total votes | 146,721 | 100.00 | ||
Republican hold |